Re: [vox-tech] how does umask work?

[Peter Jay Salzman <p@dirac.orMAPSg>]

On Tue 27 Mar 01, 10:31 AM, Henry House said: 
> On Tue, Mar 27, 2001 at 10:38:59AM -0800, Peter Jay Salzman wrote:
> > ok, i give up.  kind of looks like the number is subtracted from 666, but
> > that's not quite correct.
> > 
> > how does this work?  how does one set the x bit, for instance (not that
> > you'd want to, but i'm just curious).
> > 
> > umask 000   # rw-rw-rw-
> > umask 111   # rw-rw-rw-
> > umask 222   # r--r--r--
> > umask 333   # r--r--r--
> > umask 444   # -w--w--w-
> > umask 555   # -w--w--w-
> > umask 666   # ---------
> > umask 777   # ---------
> 
> There are four digits; the first is assumed to be octal zero if omitted.
 
are you sure?

% umask 1111
bash: umask: `1111' is not an octal number from 000 to 777

i think you're thinking of chmod, not umask.

ok, so how do i set a umask of --x--x--x ?

pete